4x^2+72x-324=0

Solution for 4x^2+72x-324=0 equation:

4x^2+72x-324=0

a = 4; b = 72; c = -324;
Δ = b2-4ac
Δ = 722-4·4·(-324)
Δ = 10368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10368}=\sqrt{5184*2}=\sqrt{5184}*\sqrt{2}=72\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72\sqrt{2}}{2*4}=\frac{-72-72\sqrt{2}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72\sqrt{2}}{2*4}=\frac{-72+72\sqrt{2}}{8}
$